求值:[2sin50°+sin10°(1+√3tan10°)]√(1-sin^2 10°)
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/09/20 07:49:19
求值:[2sin50°+sin10°(1+√3tan10°)]√(1-sin^2 10°)
1-sin²10=cos²10
所以原式=(2sin50+sin10+√3sin10*sin10/cos10)*cos10
=2sin50cos10+sin10cos10+√3sin²10
=2sin50cos10+1/2*sin20+√3(1-cos20)/2
=2sin50cos10+1/2*sin20-√3/2cos20+√3/2
=2sin50cos10+sin20cos60-cos20sin60+√3/2
=2sin50cos10+sin(20-60)+√3/2
=2sin50cos10-sin40+√3/2
=2sin50cos10-sin(50-10)+√3/2
=2sin50cos10-sin50cos10+cos50sin10+√3/2
=sin50cos10+cos50sin10+√3/2
=sin(50+10)+√3/2
=sin60+√3/2
=√3
所以原式=(2sin50+sin10+√3sin10*sin10/cos10)*cos10
=2sin50cos10+sin10cos10+√3sin²10
=2sin50cos10+1/2*sin20+√3(1-cos20)/2
=2sin50cos10+1/2*sin20-√3/2cos20+√3/2
=2sin50cos10+sin20cos60-cos20sin60+√3/2
=2sin50cos10+sin(20-60)+√3/2
=2sin50cos10-sin40+√3/2
=2sin50cos10-sin(50-10)+√3/2
=2sin50cos10-sin50cos10+cos50sin10+√3/2
=sin50cos10+cos50sin10+√3/2
=sin(50+10)+√3/2
=sin60+√3/2
=√3
求值:[2sin50°+sin10°(1+√3tan10°)]√(1-sin^2 10°)
求值:[2sin50°+sin10°(1+√3tan10°)]×√2sin80°
[2sin50°+sin10°(1+√3tan10°)]•√(sin²80°)
求值[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80°)
化简:[2sin50°+sin10°(1+根号3*tan10°)]*根号sin^280°
化简[2sin50°+sin10°(1+√3tan10°)] √(sin²80°)尽量简单点
化简[2sin50°+sin10°(1+√3tan10°)] √(2sin280°)
求[2sin50°+sin10°(1+√3tan10°0]sin80°的值
[2sin50°+sin10°(1+根号3 tan10°)]根号(2sin^2 80°)的值
2sin50 +sin10×(1+ √3tan10)
[2sin50°+sin10°(1+根号3tan10°)]乘sin10°等于?
[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)