化简【2sin50°+sin80°(1+√3tan10°)】/cos5°
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/09/20 16:40:49
化简【2sin50°+sin80°(1+√3tan10°)】/cos5°
[2sin50°+sin80°(1+√3tan10°)]/cos5°
=[2sin50°+cos10°(cos10°+√3sin10°)/cos10°]/cos5°
=[2sin50°+2(1/2*cos10°+√3/2*sin10°)]/cos5°
=[2sin50°+2(cos60°*cos10°+sin60°*sin10°)]/cos5°
=[2sin50°+2cos50°]/cos5°
=2√2*(sin50°*cos45°+cos50°*sin45°)/cos5°
=2√2sin95°/cos5°
=2√2cos5°/cos5°
=2√2
=[2sin50°+cos10°(cos10°+√3sin10°)/cos10°]/cos5°
=[2sin50°+2(1/2*cos10°+√3/2*sin10°)]/cos5°
=[2sin50°+2(cos60°*cos10°+sin60°*sin10°)]/cos5°
=[2sin50°+2cos50°]/cos5°
=2√2*(sin50°*cos45°+cos50°*sin45°)/cos5°
=2√2sin95°/cos5°
=2√2cos5°/cos5°
=2√2
化简【2sin50°+sin80°(1+√3tan10°)】/cos5°
求值:[2sin50°+sin80°(1+√3tan10°)]/√2cos5°
求值[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80°)
[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)
求值:[2sin50°+sin10°(1+√3tan10°)]×√2sin80°
求[2sin50°+sin10°(1+√3tan10°0]sin80°的值
求值:2sin50°+sin80°(1+3tan10°)1+cos10°
化简【2sin50°+sin10°(1+根号3tan10°)】乘根号下2(sin80°的平方)
化简[2sin50°+sin10°(1+根号三tan10°)]*根号[2(sin80°)平方]拜托了各位
请问这个题怎么解?sin50°+sin10°(1+根号3*tan10°)根号下2*sin80°平方
化简sin50°(1+3tan10°)
化简:sin50°(1+√3tan10°)