y(1)=4.y^{3}
y(1)=4.y^{3}
解方程:3y^2-(2y+1)(y-1)=(y-5)(y+1)
解方程3y^2-(2y+1)(y-2)=(y-5)(y-1)
y'=(x-y+1)/(x+y-3)通解
{3(x+y)+3(y+x)=1,3(x+y)+4(y-x)=-1
(3x-y)^2+(3x+y)(3x-y),x=1,y=-2
微分方程y''=3√y,x=0,y=1,y'=2
(5y+1)+ (1-y)= (9y+1)+ (1-3y);
解方程(1-3y)^2+(2y-1)^2=13(y-1)(y+1)
{4/(x+y)+6/(x-y)=3 {9/(x-y)-1/(x+y)=1
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
解3y+5/3y-6=1/2+5y-4/2y-4