设log2(3)=t,log3(4)=?
设log2(3)=t,log3(4)=?
log2(3)+log3(5)+log3(2)=?
log2 3×log3 7=log2 7
log2 4=2log3 9=3
设p=log2(3)、Q=log3(2)、R=log2【log3(2)】,则它们的大小关系
log2(3)=a,log3(7)=b.log12(56)=log3(7*8)=log3(7)+3log3(2)
设a=log3π,b=log2根号3,c=log3根号2则它们之间的大小关系
设a=log3π,b=log2根号3,c=log3根号2,则a,b,c,的大小关系为
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
log2的八次方=3 log3的81次方=4 那么log2的64次方等于多少
log2(3)*log3(4)*log4(5)*.log(k+1)(k+2)=log2(k+2) 怎么证
我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log