(x-1-√2i)(x-1+√2i)(x-2+√3i)(x-2-√3i)
(x-1-√2i)(x-1+√2i)(x-2+√3i)(x-2-√3i)
已知(2i√x+1/x^2)^n,i 是虚数单位,x∈R,n∈N.
(x+√3i)^3=log√2(下标)1/2^4 求x,
A={x|x^2-(4+i)x+k+2i=0,k∈R},B={x||x-1+xi≤√(2)^log2(3-2x)|}
X=[X;fliplr(x(i:2*N+i))]
已知2<x<3,那么I x-根号2 I+I x-根号10 I=?
∵(2x-1)+i=y-(3-y)i(2x+ay)-(4x-y+b)i=9-8i,∴
已知z=根号(3x-1)-x+(x^2-4x+3)i>0,求x=
(3x+2y)+(5x-y)i=17-2i.求x与y
如何从x^2=(-1±√3i)/2 求出x=±√[(-1±√3i)/2]
y=cos2x+sin^2x的值域是?复数1+√3i/1-i 的点位于第几象限?(1-2x)(1+x)^5的展开式中x^
# define MA(x,y) (x)*(y) int i=2; i=3/MA(i,i+2)+5; printf(“%