请教一道二元一次方程若xyz≠0,且{ 4x-5y+2z=0 ,求x:y:z的值x+4y-3z=0
请教一道二元一次方程若xyz≠0,且{ 4x-5y+2z=0 ,求x:y:z的值x+4y-3z=0
若xyz不等于0,且满足(y+z)/x=(x+z)/y=(x+y)/z,求(y+z)(x+z)(x+y)/xyz的值
若xyz不等于0,且(y+z)/x=(z+x)/y=(x+y)/z,求(y+z)(z+x)(x+y)/xyz的值?
若xy-z不等于0,且(y+x)/x=(z+x)/y=(y+x)/z,求[(y+z)(z+x)(x+y)]/xyz的值?
若4x-3y-6z=0,x+2y-7z=0且xyz≠0; 求(2x+3y+6z)/(x+5y+7z)的值?
已知:(x+y-z)/z=(x-y+z)/y+(y+z-x)/x,且xyz≠0,求代数式[(x+y)(y+z)(x+z)
已知4x-3y+z=0,x+2y-8z=0,xyz不等于0,求x+y-z/x-y+2z的值
已知x+y-z/z=x-y+z/y=-x+y+z/x,且xyz不等于0,求分式[(x+y)(x+z)(y+z)]/xyz
x*x+y*y+2z*z-2x+4y+4z+7=0,求xyz的值
若xyz不等于0,且{4x-5y+2z=0,x+4y-3z=0,求x:y:z
已知:(x+y)/z=(x+z)/y=(z+y)/x,且xyz不等于0,则分式(x+y)(x+z)(z+x)/xyz的值
解二元一次方程X+Y-5Z=0,3X-3Y-Z=0,求X:y:z