a-1-(a²/a-1)
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/10/04 22:40:01
a-1-(a²/a-1)
(4/a+2)+a-2
(1/x-3)-(1/x+3)
(4/a+2)+a-2
(1/x-3)-(1/x+3)
1、原式=((a-1)(a-1))/(a-1)-a^2/(a-1)
=(a^2-2a+1-a^2)/(a-1)
=(1-2a)/(a-1)
2、原式=4/(a+2)+((a+2)(a-2))/(a+2)
=(4+(a+2)(a-2))/(a+2)
=(4+a^2-2^2)/(a+2)
=a^2/(a+2)
3、原式=(x+3)/((x-3)(x+3))-(x-3)/((x-3)(x+3))
=((x+3)-(x-3))/((x-3)(x+3))
=6/(x^2-9)
希望对你有所帮助!
=(a^2-2a+1-a^2)/(a-1)
=(1-2a)/(a-1)
2、原式=4/(a+2)+((a+2)(a-2))/(a+2)
=(4+(a+2)(a-2))/(a+2)
=(4+a^2-2^2)/(a+2)
=a^2/(a+2)
3、原式=(x+3)/((x-3)(x+3))-(x-3)/((x-3)(x+3))
=((x+3)-(x-3))/((x-3)(x+3))
=6/(x^2-9)
希望对你有所帮助!
a-1-(a²/a-1)
化简(9-a²)/a²+6a+9÷(a²-3a)/a+3+1/a
数学因式分解计算(a²-b²)/(a²b-ab²)÷ [1+(a²+b
(a+b-1)²
已知a²-3a+1=0,求a+a分之1、a²+a²分之1和(a-a分之1)²的值
先化简,再求值:[(a²-1)/(a²-4)]•[(a+2)/(a²-2a+1
2(a²b+3ab²)-3(a²b-1)-2a²b-2
1、( )-3a²+5a-7=-2a²+2a+1
已知a+a分之一=3,求(1)a²+a²分之一
若2a²+3a+b=4,求{(a+b)(a-b)+(a-b)²+4a²(a+1)}/a的值
1、a/a-b*(b-a/b)²
已知:a(a-1)-(a²-b)=5,求a²+b²/2-ab的值