将一个任意整数插入到已排序的整数组中
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#includemain(){\x09inti,j,m,n,a[10];\x09printf("请输入10个整数:\n");\x09for(i=0;i
#include#defineSIZE20voidmain(){printf("请输入10个整数:\n");inta[SIZE];intn=10,i,j,k,b;for(i=0;i
#include#includeintmain(){inta[20]={3,6,9,23,34,56,78};inti,n;intflag=0;printf("Input:");scanf("%d",
假设是增序的算法如下,时间复杂度为O(n):#includeboolfindTwoNumber(intarray[],intlen,intx){intlow=0;inthigh=len-1;while
代码如下:#include <stdio.h>#define N 11int main(int argc,char *argv[
#includevoidarr(int*a,intn);/*定义排序函数*/voidinsert(int*a,intnum);/*插入并排序函数*/intn=10;/*定义数据个数,可修改*/void
staticvoidBubbleSort(inta[]){inttemp=0;for(inti=0;ifor(intj=0;jif(a[j]>a[j+1]){//把这里改成大于,就是升序了temp=a
inta[]={33,76,26,88,15,92,37,49},i,j.k;for(i=0;i
#include//数列由小到大排列voidinsert(inta[],intm){\x09intb[11],i,j;\x09for(i=0,j=0;i
一:#includevoidmain(){inti,j;inta[5][3];for(i=0;i
给你举个例子吧!#include#defineN5main(){intnum[N+1]={1002,1003,1006,1008,1010};/*必须多开辟一个存储单元*/inti=0,j=0,new
#includeintmain(void){\x05inti,num,t=0,z;\x05inta[10]={1,2,8,17,23,24,59,62,101};//一开始有9个加上新的1个需要的是1
publicstaticvoidmain(String[]args){int[]nums={99,88,77,66,55,44,33,22,11,0};int[]nums_new=newin
#include<stdio.h>intmain(){ inta[20]={1,7,8,17,23,24,59,62,101}; inti,j,x; x=50
答案错了!你是对的
inta[]={2,5,22,666,33,234,6,7,88,55};intc;//for(inti=0;i
voidInsert(inta[N],n){for(inti=0;i
inti,j,a[20],t,number,k;\x09\x09for(i=0;i
main(){inta[10]={0,-1,12,96,188,249,800};intx,i,j=6;printf("输入一个数:");scanf("%d',&x);a[0]=x;i=j;while
代码敲一下.#include<iostream>usingnamespacestd;classStudent{private:intid;floatscore;public:Student