化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π

化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π 化简：1.【（sin^2）(-X-π) *cos（π+X）cosX】/【tan(2π+X) *（cos^3 (-X-π) 化简cos(π/2-x)cos(π/2+x)cot(π-x)/sin(3π/2+x)cos(3π+x)tan(π+x) 求化简数学公式哦[3sin^2（x/2）+cos^2（x/2)-4sin(x/2)cos(x/2)]/tan(π+x）化 已知cos(π/2+x)=sin(x-π/2) 求sin^3(π-x)+cos(x+π)/5cos(5π/2-x)+3s 已知函数f(x)=cos(2x-π/3)+sin^2 x-cos^2 x 已知函数f(x)=cos(2x-π\3)+sin²x-cos²x 化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1 求证 tan（2π-X）sin（-2π-X）cos（6π-X）/ sin（X+3π/2)*cos（X+3π/2)=-ta 已知(x)=[sin(π-x)cos(2π-x)tan(-x+π)]/[cos(-π/2+x)] 已知sin(π/2-x)+sin(π-x)/cos(-x)+sin(2π-x)=2009,则tan(x+5π/4)等于? 三角函数已知P(-4,3) 求(cos((π/2)+x)sin(-π-x))/(cos((11π/2)-x)sin((9