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根据题意得:
x2−4≥0 4−x2≥0 x−2≠0, 解得:x=-2,则y=4, 故x2+y=8,则x2+y的立方根是2.
若y=x
若x-y=1,求代数式x(x-y)+y(y-x)+2013的值
若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于
设x>1,y>0,若x^y+x^-y=2根号2,则x^y-x^-y等于
若x+7y=y-3x,求x
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
若3x=7y,则y分之x= ,x:(x:y)=
若3x=7y,则y比x= ,x:(x+y)=
若变量x,y满足约束条件{x>=-1;y>=x;3x+2y
若实数x,y满足x-y+1>=0,x+y>=0,x
若实数x,y满足x-y+1》=0,x+y>=0,x
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