f(a)=[sin(π-x)cos(2π-x)tan(-x+3π/2)]/cot(-x -π)sin(-π--x) 化简
f(a)=[sin(π-x)cos(2π-x)tan(-x+3π/2)]/cot(-x -π)sin(-π--x) 化简
设函数f(x)=[cot(-x-π)sin(2π+x)]/[cos(-x)tan(3π-x)].(1)若f(α)=(根3
化简cos(π/2-x)cos(π/2+x)cot(π-x)/sin(3π/2+x)cos(3π+x)tan(π+x)
已知函数f(x)=sin^2x+csc^2x+cos^2x+sec^2x+tan^2x+7cot^2x,x∈(0,π/4
请问sin(x+π/2)=?cos(x+π/2)=?tan(x+π/2)=?cot(x+π/2)=?sec(x+π/2)
化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π
f(x)=|sin x+cos x+tan x+cot x+sec x+csc x|最小值
已知f(x)=sin(π-a)cos(2π-a)tan(3π/2-a)/cos(-a-π)sin(-π-a)(1)化简f
判断下列函数的奇偶性 f(x)=[sin(π/2+x)cos(π/2-x)tan(-x+3π)]/[sin(7π-x)t
已知a为第三象限角,且f(a)=sin(π-x)cos(2π-x)tan(-x+π)/sin(π+x)
已知f(x)=(sin(π-x)*cos(2π-x))/cos(-π-x)*tan(π-x),则f(-31π/3)的值为
已知函数f(x)=cos(2x-π/3)+sin^2 x-cos^2 x