1.设集合A={（X,Y)丨ax+bx+c=0}; B={(x,y）丨dx+ex+f=0}则方程（ax+bx+c)(dx

1.设集合A={（X,Y)丨ax+bx+c=0}; B={(x,y）丨dx+ex+f=0}则方程（ax+bx+c)(dx 若（3x+1）^5=ax^5+bx^5+cx^3+dx^2+ex+f,则a-b+c-d+e-f的值是 (x-3)^5=ax^5+bx^4+cx^3+dx^2+ex+f ,则a+b+c+d+e+f= ,b+c+d+e= . (x+1)^5=ax^5+bx^4+cx^3+dX^2+ex+f,求a+b+c+d+e+f,b+c+d+e,a+c+e 若（2x+1)^5=ax^5+bx^4+cx^3+dx^2+ex+f,则a-b+c-d+e-f的值= 已知等式（3x+1）^5=ax^5+bx^4+cx^3+dx^2+ex+f,求代数式a-b+c-d+e-f的值 已知等式（3x+1）^5=ax^5+bx^4+cx^3+dx^2+ex+f,求代数式-a+b-c+d-e+f的值 (x+1)^5=ax^5+bx^4+cx^3+dx^2+ex+f 求b+c+d+e 设(2x-1)^5=ax^5+bx^4+cx^3+dx^2+ex+f (2x-1)^5=ax^5+bx^4+cx^3+dx^2+ex+f 求a=?b=?c=?d=?e=?f=? （3x+1)^5=ax^5+bx^4+cx^3+dx^2+ex+f,求a-b+c-d+e-f 已知等式(2x-1)^5=ax^5+bx^4+cx^3+dx^2+ex+f,求代数式a+b+c+d+e+f的值.