急设x=2t^(2)-1,y=根号(1+t^2).求dy/dx和d^2y/dx^2
急设x=2t^(2)-1,y=根号(1+t^2).求dy/dx和d^2y/dx^2
设函数y=y(x)由x=1-e^t和y=t+e^-t确定,求dy/dx和d^2y/dx^2
设x=1+t^2、y=cost 求 dy/dx 和d^2y/dx^2 sint-tcost/4t^3 和 sint-tc
设 {x=2t^3+2 y=e^2t-1 ,求dy/dx,d^2y/dx^2
设x=t+arctan t+1,y=t的立方+6t-2,求dy/dx
设x=t^2+cost,y=1-sint,求dy/dx
x=2sin(t),y=cos(t+pie),求dy/dx,和d^2y/dx^2,在点(0,-1)
x=t^2+t y=ln(1+t) 求dy/dx
设x=e^-t y=e^-2t 求dy/dx
设y=sin2x/(1+x^2),求dy/dx,
设y=√(x^2-1)求dy/dx
设{x=ln√(1+t^2),y=arctant,求 dy/dx及d^2·y/d·x^2