tan^2θ+cot^2θ=2 怎么求θ?

tan^2θ+cot^2θ=2 怎么求θ? 证明 cotθ – tanθ = 2 cot 2θ tanα=-cotθ θ属于(π/2,π) tanθ+cotθ=3,则tan^2θ+secθcscθ+cot^2θ的值为 已知tanθ=2,求sin2θ-cos2θ／1+cot²θ的值 已知tanθ+cotθ=2,求sin^3θ-cos^3θ的值 sinΘ-cosΘ=1/2,求tanΘ+cotΘ 已知cot（π/2+θ）=2,求tanθ tanθ+cosθ=1那么(tanθ)^2+(cotθ)^2=? 化简(tanθ+cotθ)cosθ^2 [(sinθ+tanθ)/(cscθ+cotθ)]^2=(sin^2θ+tan^2θ)/(csc^2θ+cot^2θ) 求证:sin^2θtanθ+cos^2θcotθ+2sinθcosθ=tanθ+cotθ