化简[lg5*lg8000+(lg2^根三)^2]/(lg600-1/2lg0.036-1/2lg0.1)
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化简[lg5*lg8000+(lg2^根三)^2]/(lg600-1/2lg0.036-1/2lg0.1)
[lg5*lg8000+(lg2^根三)^2]/(lg600-1/2lg0.036-1/2lg0.1)
=[(lg5*(lg8+3)+(√3*lg2)^2]/[lg6+2-1/2lg(0.036*0.1)]
=[3lg5*lg2+3lg5+3*(lg2)^2]/[lg6+2-lg√(0.0036)]
=[3lg2(lg5+lg2)+3lg5]/[lg6+2-lg0.06]
=(3lg2+3lg5)/[lg(6/0.06)+2]
=3(lg5+lg2)/(lg100+2)
=3/(2+2)
=3/4
=[(lg5*(lg8+3)+(√3*lg2)^2]/[lg6+2-1/2lg(0.036*0.1)]
=[3lg5*lg2+3lg5+3*(lg2)^2]/[lg6+2-lg√(0.0036)]
=[3lg2(lg5+lg2)+3lg5]/[lg6+2-lg0.06]
=(3lg2+3lg5)/[lg(6/0.06)+2]
=3(lg5+lg2)/(lg100+2)
=3/(2+2)
=3/4
化简[lg5*lg8000+(lg2^根三)^2]/(lg600-1/2lg0.036-1/2lg0.1)
化简(lg5*lg8000+(lg2根号3)^2)/(lg600-1/2lg0.036-1/2lg0.1)
lg5乘lg8000+(lg2^根号下3)^2/lg600-(1/2)lg0.036-(1/2)lg0.1
请问lg5*lg8000+[lg2底的根号三次方]的平方 \ lg600-1\2lg0.036-1\2lg0.1 如何计
lg5·lg8000+(lg2^根三)^2+lg0.06+lg6
高中对数函数运算lg5*lg8000+3(lg2)2+lg(1\6)+lg0.06(lg2)2指lg2的平方
Lg5*Lg8000+(Lg2√3^2+Lg0.06-Lg6=?
求救啊 lg5*lg8000+(lg2)^2+lg0.06-lg6
(lg8+lg100)lg5+3(lg2)^2+lg6^-1+lg0.006
lg5/lg2*lg0.5/lg25为什么得1/2?
(lg8+lg1000)lg5+3(lg2)^2+lg^-1+lg0.006
lg5*lg8000+(lg2^根号3)^2+lg0.06-lg6=?见补充