设U={0,1,2,3}.A={x∈U|x+mx=0},若CuA={1,2}.则实数m为多少?
设U={0,1,2,3}.A={x∈U|x+mx=0},若CuA={1,2}.则实数m为多少?
设U={0,1,2,3},A={x∈U|x2+mx=0},CUA={1,2},则实数m的值为( )
设U={0,1,2,3},A={x属于U|x^2+mx=0},若CuA={1,2},则实数m=?
设U={0,1,2,3},A={x属于U|x2+mx=0},若CRB(补集)={1,2},则实数m=
设全集U={1,2,3,4},非空集合A={x丨x-5x+m=0,x属于U},求CuA及实数m的值
设全集U={-1,0,1,2},集合A={x∈U|x^2+mx=0},若A的补集={-1,2},则实数m=?(具体过程)
设集合U={1,2,3,4}且,A={x|x^2-5x+m=0},CuA={2,3},求M的值
若全集U={1,2,3,6},集合A={x|x²-mx+6},集合CuA={2,3},则实数m= 写清每一部过
设U全集={1,2,3,4},且A={x|x2-7x+m=0,x属于U},若CuA={1,2},求m的值
设全集U={1,2,3,4},且A={x|x2-5x+m=0,x属于U}若CuA={1,4},求m的值.
已知U={1,2,3,4},A={x|x^2-5x+m=0,x属于U},求CuA、m
U=R,A={-1,-2},B={x|x²+(m+1) x+m=0}.若(CuA)∩B=空集,试求m