complete the square of -x^2+6x+1

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complete the square of -x^2+6x+1
题目就是这样阿

意思是：将其(式子)配方
此题解法：
-x^2+6x+1
= - (x^2 -6x ) +1
= - (x^2 -6x + 9) +9 +1
= -(x-3)^2 + 10
更多关于配方：
配方法是一种代数的计算技巧,可以用来解二次方程式、判别解析几何中某些方程式的图形,或者用来计算微积分中的某些积分型式.配方法最主要的目的就是将一个一元二次方程式或多项式化为一个一次式的完全平方,以便简化计算.
将下方左边的二次式化成右边的形式,就是配方法的目标：
ax^2 + bx + c = a(.)^2 + k ,其中 k 是某常数
英文版定义：
In elementary algebra, completing the square is a technique for converting a quadratic polynomial of the form ax^2 + bx + c
to the form a(.)^2 + Constant
In this context, "constant" means not depending on x. The expression inside the parenthesis is of the form (x − constant). Thus one converts ax2 + bx + c to
a(x - h)^2 + k
and one must find h and k.
再问： perform the long division 又是什么意思呢
再答： perform the long division = 使用长除法（来计算）长除法就是小学老师教的那种除法计算方式，还真不好字面解释出来你可以看百度百科 http://baike.baidu.com/view/3048030.html?wtp=tt 我觉得写得不太好，你真不懂的话去书店花个7、8块买本教材看看就行了

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