大师作文网f(x)=1/(2[x]-2[1/2]),求S=f(-9)+f(-8)+……+f(10).
![f(x)=1/(2[x]-2[1/2]),求S=f(-9)+f(-8)+……+f(10).](/uploads/image/z/8694519-15-9.jpg?t=f%28x%29%3D1%2F%282%5Bx%5D-2%5B1%2F2%5D%29%2C%E6%B1%82S%3Df%28-9%29%2Bf%28-8%29%2B%E2%80%A6%E2%80%A6%2Bf%2810%29.)
f(x)=1/(2[x]-2[1/2]),求S=f(-9)+f(-8)+……+f(10).
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