设函数f(x)在【0,2】上连续,令t=2x.则∫(0,1)f(2x)dx等于?
设函数f(x)在【0,2】上连续,令t=2x.则∫(0,1)f(2x)dx等于?
特急:设函数f(x)在区间[0,2a]上连续,证明:∫ f(x)dx)=∫ [f(x)+f(2a-x)]dx,
设函数f(x)在区间[0,1]上连续,证明∫[∫f(t)dt]dx=∫(1-x)f(x)dx
一道高数题,设函数f(x)在[0,+∞)上连续,且f(x)=x(e^-x)+(e^x)∫(0,1) f(x)dx,则f(
设f(x)在(0,π/2(为闭区间)上连续,f(x)=xcosx+∫ f(t)dt 则∫ f(x)dx 等于多少积分都有
设f(x)连续 则d∫(0,2x)xf(t)dt/dx=?
设f''(x)在[0,1]上连续,f'(1)=0,且f(1)-f(2)=2,则∫(0,1)xf''(x)dx=
设函数f(x)在(-∞,+∞)上连续,且f(x)=e^x+1/e∫(0,1)f(x)dx,求f(x)
设函数f(x)在[0,1]有二阶连续导数 求 ∫(0积到1)[2f(x)+x(1-x)f''(x)]dx
设f(x)连续,d/dx∫上标x下标0tf(x^2-t^2)dt=?
设f(x)在区间[0,1]上连续,在(0,1)内可导,且满足f(1)=3∫ e^(1-x^2) f(x) dx
高数题,设函数f(x)在区间(0,1)上连续,则定积分【从-1到1】{[f(x)+f(-x)+x]x}dx=